Chemistry, 12.12.2019 07:31, annyork03

Fast! a p sublevel is represented by the quantum number (2 points) m subscript l = 1 m subscript l = 2 l = 1 l = 2

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answered: ericgalo808

l = 1 .

Explanation

Each electron in an atom comes with a unique set of four quantum numbers.

gives the main shell of an electron.

gives the type of the sub-level (a.k.a. orbital, s, p, d, f, ...) that the electron occupies.There can be more than one orbitals in a sub-level. Consider m_l

as the index for the electron's orbital.Each orbital holds two electrons. m_s

tells those two electrons apart based on the direction of each electron's spin.

The question is asking about different types of sub-levels. That depends on the angular / azimuthal quantum number, .

is an integer. It ranges from all the way to n - 1 .

An electron with l = 0

is in an

orbital.An electron with l = 1

is in a

orbital.An electron with l = 2

is in a

orbital.

In other words, the quantum number l= 1 represents a sublevel.

Reference

Vitz, Ed et al. "Quantum Numbers (Electronic)", ChemPRIME (Moore et al.). Chemistry Libretexts.

"Quantum Mechanics and Atomic Orbitals", Chemistry - The Central Science (Brown et al.). Chemistry Libretexts.

answered: Guest

u i forgot the answer?

answered: Guest

Answerthis solution will not form a precipitateexplanationsolubility equilbrium: pbf₂(s) ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is $k_{sp} = [\text{pb}^{2+}][\text{f}^- ]^2 = 4 \times 10^{-8}$ (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as $q = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}}$ then, we can interpret q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product: $\begin{aligned} q & = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}} \\ & = (1.9 \times 10^{-3} ) (3.8\times 10^{3})^2 \\ & = 2.7 \times 10^{-8} \end{aligned}$ since q = 2.7 × 10⁻⁸ < ksp = 4 × 10⁻⁸, a precipitate will not form.

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Fast! a p sublevel is represented by the quantum number (2 points) m subscript l = 1 m subscript l...