Given: 4.5 ml of 0.05 m magnesium sulfate. how many moles of magnesium sulfate do we have?

Hey there!:

Volume in liters of solution :

4.5 mL / 1000 => 0.0045

Molarity of solution = 0.05 M

Therefore  The quantity in moles of magnesium sulfate is :

n = M * V

n = 0.0045 * 0.05

n = 0.000225  moles

Hope that helps!

answer

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