Read the chemical equation.

n2 + 3h2 → 2nh3

using the volume ratio, determine how many liters of nh3 is produced if 1.2 liters of h2 reacts with an excess of n2, if all measurements are taken at the same temperature and pressure?

Answer : The volume of produced is, 0.8 liters

Explanation :

The balanced chemical reaction will be,

The mole ratio of nitrogen, hydrogen and ammonia are 1 : 3 : 2.

According to the Avogadro's Law, the volume is directly proportional to the number of moles of the gas at constant pressure and temperature.

  (At constant temperature and pressure)

or,

where,

= volume of hydrogen = 1.2 L

= volume of ammonia = ?

= moles of hydrogen = 3 mole

= moles of ammonia = 2 mole

Now put all the given values in the above formula, we get the volume of ammonia.

Therefore, the volume of produced is, 0.8 liters

The volume of ammonia produced is 0.8 L

Explanation:

At STP:

1 mole of a gas occupies 22.4 L of volume

We are given:

Volume of nitrogen gas = 1.2 L

For the given chemical reaction:

As, nitrogen gas is given in excess, it is considered as excess reagent. And, hydrogen gas is considered as the limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

(3 × 22.4) L of hydrogen gas produces (2 × 22.4) L of ammonia

So, 1.2 L of hydrogen gas will produce of ammonia

Hence, the volume of ammonia produced is 0.8 L

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.