How many sodium ions are contained in 99.6 mg of na2so3? the molar mass of na2so3 is 126.05 g/mol.

9.52x10²⁰ sodium ions

Explanation:

First, we need to convert the mass in moles (n)

n = mass/molar mass

The moalr mass is given in g/mol, so let's transform the mass in gram:

1 g 1000 mg

x g 99.6 mg

By a direct simple three rule:

1000x = 99.6

x = 0.0996 g

n = 0.0996/126.05

n = 7.90x10⁻⁴ mol of Na₂SO₃

The ionization reaction is:

Na₂SO₃ → 2Na⁺ + SO₃⁻

So, for 1 mol of Na₂SO₃, will be two moles of Na⁺ (sodium ion), then:

1 mol of Na₂SO₃ 2 moles of Na⁺

7.90x10⁻⁴ x

By a simple direct three rule:

x = 1.58x10⁻³ mol of Na⁺

Avogadro has related the number of moles with the number of the matter: atoms, ions, molecules. So, 1 mol has 6.02x10²³ ions.

1 mol 6.02x10²³

1.58x10⁻³ mol x

By a direct simple three rule:

x = 9.52x10²⁰ sodium ions

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