Iron(ii) chloride and sodium carbonate react to make iron(ii) carbonate and sodium chloride: fecl2(aq) + na2co3(s) → feco3(s) + 2nacl(aq). given 1.24 liters of a 2.00 m solution of iron(ii) chloride and unlimited sodium carbonate, how many grams of iron(ii) carbonate can the reaction produce?

287.32 g.

Explanation:

FeCl₂ + Na₂CO₃ → FeCO₃ + 2NaCl.

M = 2.0 mol/L and V = 1.24 L.

∴ n of FeCl₂ = M x V = (2.0 mol/L)(1.24 L) = 2.48 mol.

Using cross multiplication; we can calculate the no. of moles of  iron(II) carbonate can the reaction produce:

1.0 mole of FeCl₂ produces → 1.0 mole of FeCO₃, from the stichiometry.

2.48 moles of FeCl₂ produces → ??? mole of FeCO₃.

answer

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hope it

the dissolution of polymer can be thermodynamically described in 2 steps.