Sodium carbonate, na2co3(s), can be prepared by heating sodium bicarbonate, nahco3(s). 2nahco3(s) > na2co3(s) + co2(g) + h2o(g) kp = 0.23 at 100ºc if a sample of nahco3 is placed in an evacuated flask and allowed to achieve equilibrium at 100ºc, what will the total gas pressure be? 0.46 atm 0.96 atm 0.23 atm 0.48 atm 0.11 atm

The equilibrium will be

There is no gas in the reactant

The Kp expression for equilibrium will be

Kp = pH₂O X pCO₂

Given Kp =0.23

thus

0.23= pH₂O X pCO₂

The partial pressures of both will be equal, lets say "p"

0.23=p²

p=0.48

Total pressure = 0.48 + 0.48 = 0.96 atm

Answer is 0.96 atm

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

i believe the answer is three water molecules