Sodium hydroxide dissolves in water according to the equation below. if the original temperature of the solution is 50°c, which might be the temperature after a period of time? naoh(s) → naoh(aq) δh = −445.1 kj. mol

The equation shows the dissolution of NaOH in water

the minus sign of enthalpy signifies that the dissolution liberates energy or it is an exothermic process

the amount of heat released is -445.1kJ/mole

So if one mole of NaOH is dissolved the heat released will be 445.1 kJ

the heat released will raise the temperature of the solution

Thus there will be rise in temperature of the solution not a drop

Hence answer will be more than 50°C

The answer will be 90°C

sry but any answer choices

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.