What volume of o2 gas is produced from 4.60 liters of co2, assuming all values are measured at stp?

The correct answer is 4.6 liters of O₂ gas is formed.  

The concentration of CO₂ given is 4.60 liters

CO₂ (g) ↔ C (s) + O₂ (g)

Since 1 mole of CO₂ give 1 mole of O₂ upon reaction

So mole of O₂ produced = mole of CO₂

At STP, 1 mole gas contain 22.4 liter volume

So, mole of CO₂ = 4.6 / 22.4 = 0.20535

Mole of O₂ formed = mole of CO₂ = 0.20535

Volume of O₂ = 0.20535 × 22.4  

= 4.6 liters

Therefore, 4.6 liters of O₂ (g) is formed.  

the dependant variable is spilled water

the independent is the heat