Which statement is correct about the reaction that occurs between sodium hydroxide and hydrochloric acid?
it is a single replacement reaction because two new compounds of sodium and chlorine are formed.
it is an acid-base reaction because the sodium hydroxide base reacts with the hydrochloric acid to form a salt and water.
it is a single replacement reaction because sodium replaces hydrogen within a compound as sodium is higher than hydrogen in the activity series.
it is an acid-base reaction because the ions of sodium and hydrogen exchange places in an aqueous solution as hydrogen is higher than sodium in the activity series.

Answer

Hi, the correct answer is,

B. It is an acid-base reaction because the sodium hydroxide base reacts with the hydrochloric acid to form a salt and water

Explanation

When an acid reacts with a base, the products are salt and water.In this case, sodium hydroxide is a base which contains hydroxide ions, OH-, whereas hydrochloric acid is an acid that has Hydrogen ions, H+.When they react, they form sodium chloride, NaCl in aqueous solution as the salt , and additional water molecules. The equation is;

NaOH (aq) + HCl (aq) → NaCl (aq) + H2O (l)

It is an acid-base reaction because the sodium hydroxide base reacts with the hydrochloric acid to form a salt and water.

Step-by-step explanation:

The equation for the reaction is

NaOH  +  HCl  ⟶ NaCl  +  H₂O

base   +  acid ⟶  salt   + water

Thus, Option B is correct.

Options A and C are wrong, because a single displacement involves an element as one of the reactants. This reaction involves two compounds.

Option D is wrong. This is an acid base reaction because the hydrogen and hydroxide ions react with each other to form water.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

the answer is a and have a great day