Asynthesis reaction takes place when carbon monoxide and hydrogen gas react to form methanol know how many grams of methanol are produced when 2.8 g of carbon monoxide react with .50 g of hydrogen gas

3.2 g

Step-by-step explanation:  

We are given the mass of two reactants, so this is a limiting reactant problem.

We know that we will need mases, moles, and molar masses, so, lets assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r:  28.01  2.016       32.04  

          CO  +  2H₂ ⟶ CH₃OH

m/g:    2.8     0.50

Step 1.  Calculate the moles of each reactant  

Moles of CO = 2.8 g   × 1mol/28.01 g  = 0.100 mol

Moles of H₂ = 0.50 g × 1 mol/70.91 g = 0.248 mol

Step 2. Identify the limiting reactant  

Calculate the moles of CH₃OH we can obtain from each reactant.

From CO:  

The molar ratio of CH₃OH:CO is 1:1 .

Moles of CH₃OH = 0.100× 1/1  

Moles of CH₃OH = 0.100 mol CH₃OH

From H₂:  

The molar ratio of CH₃OH: H₂ is 1:2.  

Moles of CH₃OH = 0.248 × 1/2  

Moles of CH₃OH = 0.124 mol CH₃OH  

CO is the limiting reactant because it gives the smaller amount of CH₃OH.  

Step 3. Calculate the theoretical yield.

Theor. yield = 0.0100 mol CH₃OH × 32.04 g CH₃OH /1 mol CH₃OH

Theor. yield = 3.2 g CH₃OH

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

cytokinesis is the splitting of a cell membrane to form 2 identical daughter cells. it's similar to mitosis as both cells have identical copies of dna and cytokinesis is a step in the mitotic cycle.