6. gas a effuses 0.68 times as fast as gas b. if the molar mass of gas b is 17 g, what is the mass of gas a?
a) 29 g
b) 12 g
c) 7.8 g
d) 37 g

Option d) 37 g

Solution:

This question can be solved using the Graham's Law which states that:

Rate of effusion or diffusion of gas is indirectly proportional to the square root of its Molar Mass.

For two gases A and B, this formula can be written as:

= Rate of effusion of gas A

= Rate of effusion of gas B

= Molar mass of gas A

= Molar mass of gas B

We are given that, Gas A effuses 0.68 times as fast as Gas B. This means:

= 0.68 x

Using these values in the formula of Graham's law, we get:

Therefore, mass of gas A is 37 g, rounded to nearest unit.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.