Achemist reacted 17.25 grams of sodium metal with excess chlorine gas. the chemical reaction is as follows

na + cl2 → nacl

if the percentage yield of the reaction is 88%, what is the actual yield?

38.588 g ≅ 35.60 g.

Explanation:

From the balanced equation: 2Na + Cl₂ → 2NaCl,It is clear that 2.0 mole of Na reacts with 1.0 mole of Cl₂ to produce 2.0 mole NaCl.The no. of moles of Na metal reacted = mass / atomic mass = (17.25 g) / (22.989 g/mol) = 0.75 mol.

Using cross multiplication:

2.0 moles of Na metal produce → 2.0 moles of NaCl,

∴ 0.75 mole of Na metal produce → 0.75 mole of NaCl.

The calculated (theoretical) yield of NaCl = n x molar mass = (0.75 mol)(58.44 g/mol) = 43.85 g.

∵ The percentage yield = [(actual yield) / (calculated yield)] x 100.

∴ The actual yield = [(the percentage yield)(calculated yield)] / 100 = [(88 %)(43.85 g)] / 100 = 38.588 g ≅ 35.60 g.

Sorry i dont understand the question can you rephase it?

Standing in the sunlight and feeling the heat on your face (uv radiation is entering the skin, converting to infrared radiation, and is absorbed by your tissues)orstanding near a fire and feeling the heat on your skin (infrared radiation transfer)