Find the binding energy of the tritium nucleus (3 1h) in mev's.(use three significant figures in the answer) mev.

The actual binding energy is 8.48 Mev

The nucleus of tritium contains one proton and two neutrons,

Therefore; For the Tritium nucleus, the binding energy may be computed as shown below:

Total mass of 1 protons            = 1 × 1.00728 = 1.00728 amu

Total mass of 2 neutrons           = 2 × 1.00866 = 2.01732 amu

Total mass of nucleons                          =  3.02460amu

Atomic mass of tritium                            =  3.01605 amu

Mass defect Dm                                        = 0.00855 amu

But; 1 amu =931.5  MeV

Thus; Binding energy of Tritium = 0.00855 amu × 931.5  MeV/amu

                                                     = 7.964325 MeV, approximately closer to the actual 8.48 MeV.

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

warm front forms when a moist, warm air mass slides up and over a cold air mass. as the warm air mass rises, it condenses into a broad area of clouds. a warm front brings gentle rain or light snow, followed by warmer, milder weather.

hope i !