What is the number of atoms in 3.54 mol s

Answer : 2.13 ×10^24 atoms

explanation :

- One mole of (S) contains Avogadro’s number of atoms (6.02×10^23 molecules),

- Using cross multiplication,

                      1 mol of (S)             →       6.02 ×10^23 atoms

                      3.54 mol of (S)        →                   ?

Hence, the number of atoms in 3.54 mol S = 3.54 × 6.02 ×10^23 / 1 = 21.31 ×10^23 = 2.13 ×10^24 atoms ..

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm