In this chemical reaction, 325 grams of barium (ba) react completely. how many moles of lithium (li) are produced?

4.74 moles

Explanation:

2LiBr+Ba\rightarrow BaBr_2+2Li

Moles of Ba=\frac{\text {given mass}}{\text {molar mass}}

Moles of Ba=\frac{325g}{137g/mol}=2.37 moles

According to given balanced equation,

1 mole of Barium gives 2 moles of Li

Thus 2.37 moles of Barium gives=\frac{2}{1}\times 2.37=4.74 moles

Thus 4.74 moles of lithium will be produced by 135 g of barium.

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"