In 1901, thomas edison invented the nickel-iron battery. the following reaction takes place in the battery. fe(s) + 2 nio(oh)(s) + 2 h2o(l) fe(oh)2(s) + 2 ni(oh)2(aq) how many mole of fe(oh)2, is produced when 5.35 mol fe and 7.65 mol nio(oh) react?

3.825 mol of Fe(OH)2 are produced .

Explanation:

Reaction:

Fe(s) + 2 NiO(OH)(s) + 2 H2O(l) → Fe(OH)2(s) + 2 Ni(OH)2(aq)

5.35 mol Fe and 7.65 mol NiO(OH) react. For every 1 mol of Fe that reacts 2 mol of NiO(OH) are needed, then for 5.35 mol Fe, 5.35*2 = 10.7 mol of NiO(OH) are needed. Therefore, NiO(OH) is the limiting reactant.

1 mol of Fe(OH)2 is produced when 2 mol of NiO(OH) reacts, then if 7.65 mol NiO(OH) reacts, 7.65/2 = 3.825 mol of Fe(OH)2 are produced .

i think it is d. e because the next one is igneous.