How many moles of no2 will form when 3.3 moles of cu are reacted with excess hno3?

6.6 moles.

Explanation:

Cu + 4HNO₃ → Cu(NO₃)₂ + 2NO₂ + 2H₂O.

Now, using cross multiplication:

1.0 mole of Cu produces → 2.0 moles of NO₂, from the stichiometry,

∴ 3.3 moles of Cu produces → ??? moles of NO₂.

∴ the number of moles of NO₂ will form when 3.3 moles of Cu are reacted with excess HNO₃ is = (3.3 moles of Cu) (2.0 moles of NO₂) / (1.0 mole of Cu ) = 6.6 moles.

answer by yourhope:

how do models compare to real-world objects?

d. most models represent a real-world object in a simpler way.

: )

it would be a gas formation