Chemistry, 23.06.2019 12:30, floihqrrigweo

How do you interpret a chromatogram for what mixtures contain?

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answered: PinkDivaGirl02

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Chromatography is utilized to isolate blends of substances into their segments. All types of chromatography chip away at a similar guideline. They all have a stationary stage (a strong, or a fluid bolstered on a strong) and a portable stage (a fluid or a gas). A paper chromatogram can likewise be utilized to recognize substances by contrasting them and known substances. Two substances are probably going to be the equivalent in the event that:

they deliver a similar number of spots and these match in shading.

The spots venture to every part of a similar separation up the paper (have a similar R f esteem). Rƒ esteem, solutes, and solvents. The maintenance factor (Rƒ) might be characterized as the proportion of the separation ventured out by the solute to the separation gone by the dissolvable. It is utilized in chromatography to measure the measure of the hindrance of an example in a stationary stage in respect to a portable stage.

answered: Guest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

answered: Guest

Ithink is d. physical property

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