Why hydrochloric acid neutralized first when you titrate a mixture of hcl& ch3cooh against standard sodium hydroxide

Explanation:

We are given a mixture of hydrochloric acid (HCl) and acetic acid . The given mixture is a mixture of strong acid and a weak acid.

Strong acid is defined as the acid that can be get completely ionized or dissociated in an aqueous solution. Weak acid is defined as the acid which does not dissociate completely in an aqueous solution.

When a mixture of HCl and is titrated against NaOH (strong base), strong acid will get neutralized first because it is completely dissociated in the solution and can be easily neutralized.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.