In the reaction 2h2o (1)+ 2cl^- (aq)= h2(g)+cl2 (g)+ 2oh^-(aq), which substance is reduced? a. h2o b. cl c. h d. oh e. none of the above (this is not a redox reaction)

- C. H

Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.

As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in is -1. On product side, the oxidation number of hydrogen in is zero and in the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in is 0.

From above data, Oxidation number of O is -2 on both sides so it is not reduced.

Oxidation number of Cl is changing from -1 to 0 which is oxidation.

Oxidation number of H is changing from +1 to 0 which is reduction.

So, the right choice is C.H

answer: find it ur self

explanation:

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