If i have 7.7 moles of a gas at a pressure of 0.09 atm and a temperature of 329 k , what is the volume of the container that the gas is in ?

N=number of moles=7.7 moles.
P=pressure at atm=0.09 atm
T=temperature at ºK=329 ºK
R=universal gas costant=0.082 (L*atm ) / (ºK*mol)

The ideal gas law:

PV=nRT

therefore:
0.09 atm*V=7.7 moles * 0.082 (L*atn)/(ºK* mol) * 329ºK
V=(7.7 moles * 0.082 (L*atn)/(ºK* mol) * 329ºK) / (0.09 atm)=2,308.12 L

the volume is  2,308.12 litres

The correct answer is c. orbital shape. "the angular momentum quantum number l describes the shape of an orbital. it corresponds to each orbital type, i.e. (0,1,2,−1)=(s,p,d,f,g,"

The net force is 100