If kc = 4.0×10−2 for pcl3(g)+cl2(g)⇌pcl5(g) at 520 k , what is the value of kp for this reaction at this temperature?

Here we have to get the of the reaction at 520 K temperature.

The of the reaction is 1.705 atm

We know the relation between and is , where   = The equilibrium constant of the reaction in terms of partial pressure,  = The equilibrium constant of the reaction in terms of concentration and N = number of moles of gaseous products - Number of moles of gaseous reactants.

Now in this reaction, PCl₃ + Cl₂ ⇄ PCl₅

Thus number of moles of gaseous product is 1, and number of moles of gaseous reactants are 2. Thus N = |1 - 2| = 1 mole

The given value of   is 4.0×10⁻²

The molar gas constant, R = 0.082 L. Atm. mol⁻¹. K⁻¹ and temperature, T = 520 K.

On plugging the values in the equation we get,

Or, = 1.705 atm

Thus, the of the reaction is 1.705 atm

oh it is true if thats what you are asking

aquifers are bounded above and below by impermeable rock. the driving force of groundwater movement in confined aquifers is pressure, rather than gravity.