Determine δg when [ni(nh3)62+] = 0.010 m, [ni2+] = 0.0010 m, and [nh3] = 0.0050 m. in which direction will the reaction proceed to achieve equilibrium? ni2+(aq) + 6 nh3(aq) ⇌ ni(nh3)6 2+(aq) is kf = 5.6 × 108 at 25°

Given:

The reaction is

We know that

Δ

Δ

Δ

For the given reaction the reaction quotient will be :

Q = \frac{[Ni(NH_{3} )_{6} ^{+2}] }{[Ni^{+2} ][NH_{3}]^{6}

On putting values

Q  will be equal to =

The relation between standard and other free energy change is

ΔG = Δ

Thus

ΔG = (-49906.8) + (8.314)(298) ( ln ()

ΔG = (-49906.8) + 84466

ΔG = 34535 J / mol K

ΔG  is positive so reaction is not spontaneous in forward direction

It will proceed in reverse direction, it will move from product to reactant

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.