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P₄O₆ + 2O₂ ⟶ P₄O₁₀

Step-by-step explanation:

We have two equations:  

(I)  P₄ + 3O₂ → P₄O₆  

(II) P₄ + 5O₂ → P₄O₁₀

From these, we must devise the target equation:  

(III) P₄O₆ + __O₂ ⟶ P₄O₁₀

The target equation has P₄O₆ on the left, so you reverse Equation (I).  

(IV) P₄O₆ ⟶ P₄ + 3O₂

The target equation has P₄O₁₀ on the right, so we rewrite Equation (II).  

(II) P₄ + 5O₂ → P₄O₁₀

Now, you add Equations (IV) and (II), cancelling species that appear on opposite sides of the reaction arrows.

We get the target Equation (III):  

(IV)           P₄O₆ ⟶ P₄ + 3O₂

(II)   P₄ +  52O₂ ⟶ P₄O₁₀

(III)  P₄O₆ + 2O₂ ⟶ P₄O₁₀

the answer to your question is c

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