How many grams of n2 are produced from 100. g of nh3 in the following reaction? 4nh3(g) + 6no(g) → 5n2(g) + 6h2o(l) a) 165 g b) 132 g c) 125 g d) 206 g e) 7.35 g

Answers:

D) 206. g

Step-by-step explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:  17.03                   28.02

          4NH₃ + 6NO ⟶ 5N₂ + 64H₂O

m/g:  100.

(1) Calculate the moles of NH₃

n = 100. g NH₃ ×1 mol NH₃/17.03 g NH₃

n = 5.872 mol NH₃

(2) Calculate the moles of N₂

The molar ratio is (5 mol N₂/4 mol NH₃)

n = 5.872 mol NH₃ × (5mol N₂/4 mol NH₃)

n = 7.340 mol

(3) Calculate the mass of N₂

Mass of N₂ = 7.340 mol N₂ × (28.02 g N₂/1 mol N₂)

Mass of N₂ = 206 g N₂

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