How many grams of nano3 will precipitate if a saturated solution of nano3 in 200 g of water at 50°c is cooled to 20oc? assume the following solubility values for nano3: 114.0g/100g h2o at 50oc; 88.0g/100g h2o at 20oc

Sodium nitrate is less soluble in cool water than warm. 144.0 grams are dissolved at 50°C, multiplying by 2 since there are 200 grams H2O = 72.0 grams. Then 88.0 grams are dissolved at 20°C, again multiplying by 2= 44.0 grams. Subtracting both we get the final value that 28.0 grams precipitate from the saturated solution.

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