How is the number of valence electrons related to the ionization energy of an element? (1 point) low ionization energy correlates to elements with fewer valence electrons. elements with higher ionization energy tend to have less valence electrons. atoms with nearly full valence electron shells have lower ionization energy. high ionization energy indicates a low likelihood to gain valence electrons.

High ionization energy indicates a low likelihood to gain valence electrons.

Explanation: Ionization energy is the energy required to remove the most loosely bound electron from an gaseous atom.

Thus atoms with smaller radii will have high ionization energies as the electrons are tightly held by the nucleus.

Moreover the atoms with half or fully filled configurations are stable , so high energy is required to remove the electron.Thus they have high value of ionization energy.  And there is less likelihood for them to gain electrons as that would make them unstable.

what's the question?

explanation:

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.