Place the following compounds in order of increasing strength of intermolecular forces. co2 f2 nh2ch3 a) nh2ch3 < co2 < f2 b) f2 < nh2ch3 < co2 c) nh2ch3 < f2 < co2 d) f2 < co2 < nh2ch3

It should be D) since NH2CH3 has hydrogen atoms in the formula, it will tend to be polar-so dipole-dipole, dispersion forces are always there, and then hydrogen bonding is the strongest intermolecular force. There are no Ion-dipole attractions present in any of these compounds. F2 should have the weakest strength in Intermolecular forces, since it is not polar so only dispersion forces should be found present. Which leaves CO2 to be in the middle with Dipole-dipole attractions and dispersion forces.

D)  F2 < CO2 < NH2CH3

Explanation:

NH2CH3 - strongest due to the hydrogen bonds (other bonds are present but the Hydrogen bonds are key as it has the strongest attraction)

CO2 -  Second strongest due to Dipole-Dipole attraction and London dispersion

F2 - Weakest - Nonpolar, so only dispersion forces are in effect.

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

c

explanation: