You are performing a reaction with 1.7 moles of hydroiodic acid and 3.43 moles of zinc bromide: 2hi + znbr2 → 2hbr + zni2. how many moles of zinc iodide can be made?

number of moles of HI = 1.7 mol

number of moles of ZnBr2 = 3.43 mol

2HI + ZnBr2 → 2HBr + ZnI2

every 2 mole of HI will require 1 mole of ZnBr2

mole of ZnBr2 that will react = 1.7 / 2 = 0.85 mol

Therefore HI is the limiting reactant and not all ZnBr2 will be reacted

For every 2 mole of HI will form one mole ZnI2

1.7/2 = 0.85 mol of ZnI2 formed

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms