5. the table below gives formulas for some ionic compounds formed when cations (x, y, z) combine with anions (a, l, d, f). a. what are the charges for each cation and anion (4 points) b. write formulas for compounds 1-4 (2 points)

for B

1) X3D2

2. YA

3. Y2F

4. Z2L3

I don't know how to do a

cation - ( x, y ,z)

Anion - ( A,L, D,F )

consider : P+m - cation

Q^n- : Anion

(1) x + A : xa^2

x^2, A- —> xa2

x + L : XL , x^2 + L^2- —> XL

x + D : (1) x + f = XF : x^2 + F^2-

(2) Y + A = (2) Y + L : Y2L : ( Y+, L^-2 —> Y2L )

Y + D : Y3D : Y+, D3- : Y3d

Y+ F : Y^+ + F^-2 = Y2F (3)

(4)

Z + A : z^3+ + A- —>  ZA3 (Z+L= 4)

Z + D : ZD : Z ^+3, D^3- —> ZD

Z + F : Z2f3 : Z^3+  + F^2- —-> Z3F2

*

X^2, y^+1, Z^+3 - cation

A^-1, L^-2, D^-3, F^-2 : Anion

part B

1 : x^2 + D^3- = X3D2

2 : Y+ A : Y^+  +  A - = YA

3 : Y + F : Y^+ + F^2- = YF2

4 : Z+ L = z^3 + L^2- = Z2L3

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation:

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