For elements in the third row of the periodic table and beyond, the octet rule is often not obeyed. a friend of yours says this is because these heavier elements are more likely to make double or triple bonds. another friend of yours says that this is because the heavier elements are larger and can make bonds to more than four atoms at a time. part a which friend is most correct?

The reason that some of the elements of period three and beyond are steady in spite of not sticking to the octet rule is due to the fact of possessing the tendency of forming large size, and a tendency of making more than four bonds. For example, sulfur, it belongs to period 3 and is big enough to hold six fluorine atoms as can be seen in the molecule SF₆, while the second period of an element like nitrogen may not be big to comprise 6 fluorine atoms.  

The existence of unoccupied d orbitals are accessible for bonding for period 3 elements and beyond, the size plays a prime function than the tendency to produce more bonds. Hence, the suggestion of the second friend is correct.  

ill try to . no promises tho.

explanation:

your answer would be “dry”