When a metal was exposed to photons at a frequency of 4.08× 1015 s–1, electrons were emitted with a maximum kinetic energy of 5.30× 10–19 j. calculate the work function of this metal. also, what is the maximum number of electrons that could be ejected from this metal by a burst of photons (at some other frequency) with a total energy of 6.36× 10–7 j? i would love an explanation if that is possible!

Answer :

The work function of this metal is,

The maximum number of electrons released =

Solution : Given,

Frequency =

Kinetic energy =

Total energy =

First we have to calculate the work function of the metal.

Formula used :

where,

K.E = kinetic energy

h = Planck's constant =

= frequency

w = work function

Now put all the given values in this formula, we get the work function of the metal.

By rearranging the terms, we get

Therefore, the works function of the metal is,

Now we have to calculate the maximum number of electrons released.

The maximum number of electrons released =

The maximum number of electrons released =

Therefore, the maximum number of electrons released =

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