During science, jim's teacher gives this simple rule to use as a first attempt to increase solubility of the solute and the rate of solution. a) decrease the temperature of water. b) agitate the solute in the solvent. c) increase the concentration of salt. d) increase particle size of the solute.

Option (B) is the correct answer.

Explanation:

To agitate the solute particles means to increase the collisions between them. This can be done by increasing the temperature because when temperature is increased then solute particles break into its constituent particles.  

When particles become smaller in size then the solubility increases and thus rate of solution will also increase.

Whereas when temperature of water is decreased then there will be no collision between the particles. As a result, particles will not break into its constituent particles so there will be no solubility of solute into the solution.

Increase the concentration of salt will make the solution more concentrated. As a result, solubility of solution will be very low and rate of solution will decrease.

On increasing the particle size of the solute will take much more time to dissolve in the solution. As a result, both solubility and rate of solution decreases.

Thus, we can conclude that out of the given options, agitate the solute in the solvent will increase solubility of the solute and the rate of solution.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml