What is the net cell reaction for the cobalt-silver voltaic cell? express your answer as a chemical equation?

The net ionic equation for the cobalt-silver voltaic cell is

Explanation: In cobalt-silver voltaic cell, one half of the cell consists of cobalt electrode immersed in solution ( which means that are present in the solution) and other half of the cell consists of the Ag electrode immersed in solution ( which means that is present in the solution)

The two electrodes are joined by the copper wire. The cobalt electrode acts as an anode and the silver electrode acts a  cathode.

At anode, oxidation reaction takes place and at cathode, reduction reaction takes place.

At Anode :                    

At Cathode:                  

Net ionic equation:  

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

3 hours because it is a decent distance.