The electron configuration below represents a ground-state atom of which element? 1s22s22p63s23p4

The given electronic configuration has been representing the ground state of sulfur atom.

The electronic configuration has been the electron address in an atom. It has been the representation of the number of electrons present in the quantum subshell of each shell.

The number of electrons has been calculated with the superscript of each quantum level. The number of  electrons in the given electronic configuration has been given as:

The number of electrons in the sample has been a representation of the atomic number of the element. The number of electrons in the given sample has been 16. Thus, the atomic number of the sample has been 16.

The element with 16 atomic number is Sulfur. Thus, the given electronic configuration has been representing the ground state of sulfur atom.

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The electron configuration below represents a ground-state atom of which element? 1s22s22p63s23p4

Sulfur

Explanation:

There are two ways to get the answer.

1. Count the electrons.

The electron configuration is 1s² 2s²2p⁶ 3s²3p⁴.

The numbers in the superscripts tell you how many electrons are in each subshell.

They add up to 16, and element 16 is sulfur.

2. Look at the outermost shell.

The outermost shell has the electron configuration 3s²3p⁴.

This tells you that the element is in Period 3 and has six valence electrons.

Start at the left of Period 3 (Na). Count six places to the right, and  you come to sulfur.

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.