How many grams of oxygen gas are needed to react completely with 38.442 grams of sulfur dioxide gas? so2(g) + o2(g) --> so3(g) (needs to be balanced)

19.221 grams of oxygen gas are needed to react completely with 38.442 grams of sulfur dioxide gas.

Explanation:

Given :

After balancing,

According to reaction ,2 moles of reacts with one mole of then 1.2013 moles of will react with :

Mass of required =

19.221 grams of oxygen gas are needed to react completely with 38.442 grams of sulfur dioxide gas.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

m=9

step-by-step explanation: