How many grams of nacl are required to make 150.0ml of a 5.000 m solution

The  number of  grams of NaCl  required  to make 150.0 ml of a 5.000m solution  is  43.875  grams

calculation

Step 1:  calculate  moles of NaCl

moles=  molarity x  volume in liters

volume in liters =  150.0  ml/1000= 0.15  l

moles is=  5.000mol/l  x0.15  l  =0.75  moles

Step2 :  find  mass

mass=  moles  x molar  mass

molar mass  of NaCl= 23 +35.5 = 58.5  g/mol

mass= 0.75  moles x58.5 g/mol = 43.875 grams

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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