What is the maximum number of moles of al2o3 that can be produced by the reaction of .4 mol of al with .4 mol of o2

There can  0.2 moles Al2O3 be produced

Explanation:

Step 1: Data given

Moles of Al = 0.4 moles

Moles of O2 = 0.4 moles

Step 2: The balanced equation

4Al + 3O2 → 2Al2O3

Step 3: Calculate the limiting reactant

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

Al is the limiting reactant. It will completely be consumed. (0.4 moles).

O2 is in excess. Therer ill react 3/4*0.4 = 0.3 moles O2

There will remain 0.4 -0.3 = 0.1 mol

Step 4: Calculate moles of Al2O3

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

For 0.4 moles Al we'll have 0.4/2 = 0.2 moles Al2O3

There can  0.2 moles Al2O3 be produced

its first and third is your answer i did the qustion the fourth isnt right