What is the volume (in liters) of 1.00 mole of krypton gas that has a pressure of 1140 mm hg and a temperature of 25.0°c? (r= 0.0821 l atm/ mol k)?

The  volume (in  liters )  of 1.00   moles  of  krypton gas   is 16.31 L

 Calculation

The volume of krypton  is calculated using ideal gas  equation

that is PV=nRT  where

P(pressure) =1140 mm hg

convert  1140 mmhg  into atm

= 1 atm =  760  mmhg

  ? atm  = 1140 mm hg

by cross  multiplication

= (1 atm x1140  mmhg) /760  mmhg = 1.5 atm

V (volume) =   ?  L

n( number of moles) = 1.00 mole

R (gas constant) = 0.0821  L atm / mol.K

T (temperature) = 25 c into kelvin = 25+273 = 298 K

make  v  the subject of the formula  by dividing both side by P

V   = nRT/P

V= [(1.00 mole  x 0.0821  L.atm/mol.k  x 298 K) / 1.5 atm ] =16.31 L

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.