Which chemical equation shows the incomplete combustion of methane? a. c3h8 + 5o2 → 3co2 + 4h2o b. 2ch4 + 3o2 → 2co + 4h2o c. ch4 + 2o2 → co2 + 2h2o

Combustion is a chemical reaction in which a hydrocarbon reacts with oxygen to form carbon dioxide (CO2) and water (H2O). In other words, all the carbons get converted to CO2 while all the hydrogens get converted into H2O.

Incomplete combustion however, results in the formation of carbon monoxide (CO) and H2O.

Methane is a hydrocarbon with a molecular formula CH4. Thus complete combustion of methane can be expressed as-

CH4 + 2O2 → CO2 + 2H2O

Ans (C)

Answer : The incomplete combustion equation of methane is, (B)

Explanation :

Combustion reaction : It is defined as the reaction in which a hydrocarbon react with oxygen to give carbon dioxide and water as a product.

As per question, the combustion of methane (a hydrocarbon) also gives carbon dioxide and water as a product.

The balanced combustion reaction of methane will be,

By the stoichiometry we can say that, 1 mole of methane react with 2 moles of oxygen to give 1 mole of carbon dioxide and 2 moles of water.

So, option (B) is an incomplete combustion reaction of methane and option (A) is the balanced combustion reaction of pentane.

Hence, the incomplete combustion equation of methane is, (B)

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml