Calcium nitrate reacts with sodium phosphate to form sodium nitrate and calcium phosphate. given 96.1 grams of calcium nitrate, what’s the theoretical yield of calcium phosphate? use the periodic table and the polyatomic ion resource. the mass of calcium phosphate the reaction can produce is blank grams.

99.56 g.

Explanation:

3Ca(NO₃)₂ + 2Na₃PO₄ → 6NaNO₃ + Ca₃(PO₄)₂.

It is clear that 3.0 moles of Ca(NO₃)₂ react with 2.0 moles of Na₃PO₄ to produce 6.0 moles of NaNO₃ and 1.0  mole of Ca₃(PO₄)₂.

n = mass/molar mass = (96.1 g)/(164.088 g/mol) = 0.5857 mol.

Using cross multiplication:

3.0 moles of Ca(NO₃)₂ produce → 6.0 moles of NaNO₃.

0.5857 moles of Ca(NO₃)₂ produce → ??? moles of NaNO₃.

∴ The no. of moles of NaNO₃ = (6.0 mol)(0.5857 mol)/(3.0 moles) = 1.171 mol.

∴ The no. of grams of NaNO₃ = (no. of moles of NaNO₃)(molar mass) = (1.171 mol)(84.99 g/mol) = 99.56 g.

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