Determine the molar solubility of agbr in a solution containing 0.150 m nabr. ksp (agbr) = 7.7 ă— 10-13. determine the molar solubility of agbr in a solution containing 0.150 m nabr. ksp (agbr) = 7.7 ă— 10-13. 5.1 ă— 10-12 m 3.9 ă— 10-13 m 0.150 m 5.8 ă— 10-5 m 8.8 ă— 10-7 m

Hey there!:

Given the reaction:

 NaBr  ⇌  Na⁺ +  Br⁻

  ↓              ↓         ↓

0.150M      0.150M     0.150M

AgBr ⇌ Ag⁺   + Br⁻

 ↓            ↓          ↓

 x            x         0.150M

Therefore:

Ksp = x * 0.150

x = ( 7.7 * 10⁻¹³ ) / 0.150

x = 5.1 * 10⁻¹²

Answer B

Hope that helps!

2b2t

explanation:

2b2t

there is none because earth is stationary and flat.