How much heat is required to raise the temperature of 65.8 grams of water from 31.5ºc to 46.9ºc? (the specific heat for water is 4.18 j/g·ºc)

4235.7J or 4.2KJ

Explanation:

The heat required to raise the temperature of water is given by

H= mcθ

Where

H= heat required=

m= mass of the water body=65.8 grams

c= heat capacity of the water= 4.18 J/g·ºC

θ=temperature change= 46.9°C- 31.5°C= 15.4°C

H= 65.8 ×4.18 × 15.4= 4235.7J or 4.2KJ

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a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.