The ksp of manganese(ii) carbonate, mnco3, is 2.42 × 10-11. calculate the solubility of this compound in g/l.

Answer :  The solubility of this compound in g/L is .

Solution : Given,

Molar mass of = 114.945g/mole

The balanced equilibrium reaction is,

At equilibrium                         s       s

The expression for solubility constant is,

Now put the given values in this expression, we get

The value of 's' is the molar concentration of manganese ion and carbonate ion.

Now we have to calculate the solubility in terms of g/L multiplying by the Molar mass of the given compound.

Therefore, the solubility of this compound in g/L is .