Given the following electronic configurations, identify how many valence electrons each atom has. a= b= c=

Answer : Valence electrons in atom A = 1, B = 6 and C = 2.

Explanation :

Valence electrons means the outermost electrons are the ones which involved in bonding. Electrons are arranged in energy levels or shells.

Valence electrons are found in the highest energy orbitals of an element.

The electronic configuration of (Na) is . The highest energy orbital is 3s orbital which contains 1 electron. So,

        The number of valence electrons in (Na) = A = 1

Similarly,

The electronic configuration of (O) is . The highest energy orbital are 2s and 2p orbitals which contains (2 + 4) = 6 electrons. So,

       The number of valence electrons in (O) = B = 6

The electronic configuration of (Fe) is . The highest energy orbital is 4s orbital which contains 2 electrons. So,

       The number of valence electrons in (Fe) = C = 2

Atomicity occurs to prevent updates of the database occurring only partially, which can cause greater problems than rejecting the whole series outright.some are monatomic, diatomic, triatomic etc because it shows the number of atoms. for example, monatomic means it contains only one atom.

Ethene molecular fórmula= c2h4molecular weight = 29.046g/molhope it : )