Answers: 1
![[Xe]4f^{14}5d^{2}6s^{2}](/tpl/images/0049/1712/932b8.png)
. It is a transition metal as it has incompletely filled d-orbital so, it will lose electrons to attain stability.![[Xe]4f^{14}5d^{10}6s^{2}6p^{6}](/tpl/images/0049/1712/3863b.png)
. Since it is a noble gas it has completely filled orbitals so, it will neither lose nor gain electrons.![[Ne]3s^{2}3p^{2}](/tpl/images/0049/1712/54c8d.png)
and it is a non-metal. So, it will gain electrons to complete its octet.![[Ne]3s^{2}3p^{4}](/tpl/images/0049/1712/98b37.png)
and it is a non-metal. So, it will gain electrons to complete its octet.![[Ne]3d^{10}4s^{2}4p^{4}](/tpl/images/0049/1712/227f1.png)
and it is a non-metals. So, it will gain electrons to complete its octet.
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