Calculate the wavelength of a photon of energy 5.518 × 10-26 joules. (planck's constant is 6.626 × 10-34 joule seconds, the speed of light is 2.998 × 108 m/s) 3.6 m 0.277 m 1.096 m 2.586 m

The wavelength of a photon of energy 5.518 × 10-26 joules is 3.6 m. The energy of the photon is: E = h * f, where h is Planck's constant and f is the frequency. The frequency of the photon is: f = c/λ, where c is the speed of light and λ is the wavelength. Therefore: E = h * f = h * c / λ. We have that E = 5.518 × 10^-26 J; h = 6.626 × 10^-34 Js; c = 2.998 × 10^8 m/s. Substitute this in the formula for the energy of the photon: 5.518 × 10^-26 J = 6.626 × 10^-34 Js * 2.998 × 10^8 m/s / λ. 5.518 × 10^-26 J = 1.986 × 10^-25 Jm / λ. λ = 1.986 × 10^-25 Jm / 5.518 × 10^-26 J. λ = 0.36 × 10 m = 3.6 m.

Answer : The wavelength of a photon is, 3.6 m

Explanation :

where,

E = energy of photon =

h = Planck's constant =

c = speed of light =

= wavelength of a photon = ?

Now put all the given values in the above formula, we get the wavelength of a photon.

Therefore, the wavelength of a photon is, 3.6 m

the temperature of the gas, in k, not celsius.

just did the assignment and the answer was #1 +2 n