Aparticle has a mass of 2 × 10-30 kg and an uncertainty in its velocity of 102 m/s. what is the minimum possible uncertainty in position that the particle can have so as not to violate the uncertainty principle?

m = mass of the particle = 2 x 10⁻³⁰ kg

Δv = uncertainty in velocity of the particle = 10² m/s

Δx = uncertainty in position of the particle = ?

h = plank's constant = 6.63 x 10⁻³⁴ J-s

uncertainty principle is given as

m Δx Δv ≥ h/(4π)

inserting the values

(2 x 10⁻³⁰) Δx (10²) ≥ (6.63 x 10⁻³⁴)/(4(3.14))

Δx ≥ 2.64 x 10⁻⁷ m

so minimum possible uncertainty is 2.64 x 10⁻⁷ m

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

i wish i could but this one is weird give me abc and i can solve it.