What is the average atomic mass of 125 atoms of uranium if there are 10 atomd of u-234, 75 atoms of u-235, and 40 atoms of u-238?

Answer is: the average atomic mass of 125 atoms of uranium is 235.88.

ω(U-234) = 10 ÷ 125.

ω(U-234) = 0.080.

ω(U-235) = 75 ÷ 125.

ω(U-235) = 0.60.

ω(U-238) = 40 ÷ 125.

ω(U-238) = 0.320.

Average atomic mass of atoms of uranium =

Ar(U-234) · ω(U-234) + Ar(U-235) · ω(U-235) + Ar(U-238) · ω(U-238).

Average atomic mass of atoms of uranium =

234 · 0.08 + 235 · 0.6 + 238 · 0.32.

Average atomic mass of atoms of uranium = 18.72 + 141 + 76.16.

Average atomic mass of atoms of uranium = 235.88.

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.

the correct answer would be b. amelia, because the particals of gas move really fast (charged particals) and gas also has a lot of room (particals move independently) so the only answer that has both of those is amelia's.