If 1200 j of heat were absorbed by a 25 g block of iron, by how much would the temperature of the iron increase?

m = mass of the block of iron = 25 g

Q = heat absorbed by the block of iron = 1200 J

ΔT = increase in the temperature of iron due to heat absorbed = ?

c = specific heat of block of iron = 0.450 J/(g C)

Heat absorbed by the block of iron is given as

Q = m c ΔT

inserting the values in the above formula

1200 = 25 (0.450) ΔT

1200 = (11.25) ΔT

ΔT = 1200/11.25

ΔT = 106.67 C

answer: mercury

explanation:

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol